MCQ
The conversion of $Pb{O_2}$ to $Pb{(N{O_3})_2}$is
- AOxidation
- ✓Reduction
- CNeither oxidation nor reduction
- DBoth oxidation and reduction
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$R - X\xrightarrow{{KCN}}A\mathop {\xrightarrow{{NaOH}}}\limits_{{H_2}O} $ $B$ is
[Atomic numbers of $Cr =24$ and $Mn =25$ ]
$(A)$ $Cr ^{2+}$ is a reducing agent
$(B)$ $Mn ^{3+}$ is an oxidizing agent
$(C)$ Both $Cr ^{2+}$ and $Mn ^{3+}$ exhibit $d^4$ electronic configuration
$(D)$ When $Cr ^{2+}$ is used as a reducing agent, the chromium ion attains $d^5$ electronic configuration