- ✓$HMn{O_4}$
- B$HMn{O_5}$
- C${H_2}Mn{O_4}$
- D${H_2}Mn{O_3}$
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ppt $\rightarrow$ colour
Assertion $A:$ A mixture contains benzoic acid and napthalene. The pure benzoic acid can be separated out by the use of benzene.
Reason $R:$ Benzoic acid is soluble in hot water.
In the light of the above statements, choose the most appropriate answer from the options given below.
${H_2}O\left( g \right) + C\left( s \right) \to CO\left( g \right) + {H_2}\left( g \right);\Delta H = 131\,kJ$
$CO\left( g \right) + \frac{1}{2}{O_2}\left( s \right) \to C{O_2}\left( g \right);\Delta H = - 282\,kJ$
${H_2}\left( g \right) + \frac{1}{2}{O_2}\left( s \right) \to {H_2}O\left( g \right);\Delta H = - 242\,kJ$
$C(s) + O_2(g) \to CO_2(g); \Delta H = X\,kJ$
The value of $X$ will be......$kJ$