MCQ
The correct increasing order for bond angles among $\mathrm{BF}_3, \mathrm{PF}_3$ and $\mathrm{C} / \mathrm{F}_3$ is :
  • A
     $\mathrm{PF}_3<\mathrm{BF}_3<\mathrm{C} \ell \mathrm{F}_3$
  • B
     $\mathrm{BF}_3<\mathrm{PF}_3<\mathrm{C} / \mathrm{F}_3$
  • $\mathrm{C} / \mathrm{F}_3<\mathrm{PF}_3<\mathrm{BF}_3$
  • D
     $\mathrm{BF}_3=\mathrm{PF}_3<\mathrm{C} \ell \mathrm{F}_3$

Answer

Correct option: C.
$\mathrm{C} / \mathrm{F}_3<\mathrm{PF}_3<\mathrm{BF}_3$
c
$Image$

Order of bond angle is

$\mathrm{ClF}_3<\mathrm{PF}_3<\mathrm{BF}_3$

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