MCQ
The correct increasing order of adjacent bond angle among $BF_3 ,PF_3$ and $ClF_3$
- A$BF_3 < PF_3 < ClF_3$
- B$PF_3 < BF_3 < ClF_3$
- ✓$ClF_3 < PF_3 < BF_3$
- D$BF_3 = PF_3 = ClF_3$
✓
Answer
Correct option: C.
$ClF_3 < PF_3 < BF_3$
c
The bond angle in $BF _3$ is $120^{\circ}$ since $B$ is $sp ^2$ - hybridized. In $PF _3, P$ is $sp ^3$ - hybridized but the bond angle is little less that $109^{\circ} .28$ (but far greater than $90^{\circ}$ ) due to bond pair - Ione pair repulsion. In $CIF _3, Cl$ is $sp ^3 d$ hybridized. It has $T$ - shape and hence the bond angle is around $90^{\circ}$. Therefore the correct order of increasing bond angle is $ClF _3\,< \,PF _3\,<\, BF _3$
The bond angle in $BF _3$ is $120^{\circ}$ since $B$ is $sp ^2$ - hybridized. In $PF _3, P$ is $sp ^3$ - hybridized but the bond angle is little less that $109^{\circ} .28$ (but far greater than $90^{\circ}$ ) due to bond pair - Ione pair repulsion. In $CIF _3, Cl$ is $sp ^3 d$ hybridized. It has $T$ - shape and hence the bond angle is around $90^{\circ}$. Therefore the correct order of increasing bond angle is $ClF _3\,< \,PF _3\,<\, BF _3$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following is correct for ${N_2}$ triple bond
→The number of photons emitted by a monochromatic (single frequency) infrared range finder of power $1\, \mathrm{~mW}$ and wavelength of $1000 \,\mathrm{~nm}$, in $0.1$ $second$ is $\mathrm{x}\, \times 10^{13}$. The value of $\mathrm{x}$ is ..... .
→(Nearest integer)
$\left(\mathrm{h}=6.63 \times 10^{-34}\, \mathrm{Js}, \mathrm{c}=3.00 \times 10^{8} \,\mathrm{~ms}^{-1}\right)$
The boiling point of a compound is raised by
Haemoglobin contains $0.33\%$ of iron by weight. The molecular weight of haemoglobin is approximately $67200$. The number of iron atoms (At. wt. of $Fe = 56$) present in one molecule of haemoglobin is
→The correct order of $H - M - H$ bonds angle is
→In the gas phase reaction, ${C_2}{H_4} + {H_2} $ $\rightleftharpoons$ ${C_2}{H_6}$, the equilibrium constant can be expressed in units of
→The molar conductivity of a $0.5\, mol/dm^3$ solution of $AgNO_3$ with electrolytic conductivity of $5.76 \times 10^{-3}\, S\, cm^{-1}$ at $298\, K$ is ......... $S\, cm^2/mol$.
→Highest covalent character is found in
Dimerisation in carboxylic acid is due to
Select the suitable reagent for above conversion.
