MCQ
The correct increasing order of polarising power is
- A$Ca^{2+} < Mg^{2+} < Be^{2+} < K^{+}$
- B$Mg^{2+} < Be^{2+} < K^{+} < Ca^{2+}$
- C$Be^{2+} < K^{+} < Ca^{2+} < Mg^{2+}$
- ✓$K^{+} < Ca^{2+} < Mg^{2+} < Be^{2+}$
ratio increases and thus polarising power increases. For $B e^{2+}, M g^{2+}, C a^{2+}$, since charge is same and size is in the order of $\mathrm{Ca}^{2+}>M g^{2+}>\mathrm{Be}^{2+}$, the
order of polarising power is $\mathrm{Ca}^{2+}<\mathrm{Mg}^{2+}<\mathrm{Be}^{2+}$
Charge of $K^{+}$ is lowest and size is larger than $\mathrm{Ca}^{2+}$ so its polarising power is lowest.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$[CH_3CH(CH_3)]_2 \,C(CH_2CH_3)C(CH_3) C(CH_2CH_3)_2$
