MCQ
The correct $\text{IUPAC}$ name of the compound is?
- A$2-$ethyl$-1-$chlorocyclohexanol.
- B$4-$chloro$-5-$ethylcyclhexanol.
- C$4-$hydroxy$-2-$ethyl$-1-$chlorocycloheane.
- ✓$4$ chloro$-3-$ethylcyclohexanol.
✓
Answer
Correct option: D.
$4$ chloro$-3-$ethylcyclohexanol.
$-OH$ group is given preference over $Cl$ group so$, 1$ number to carbon attach to $-OH$ group
so$, 4-$chloro$-3$ ethyl$-$cyclohexan $-1-ol.$
so$, 4-$chloro$-3$ ethyl$-$cyclohexan $-1-ol.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which one of the following species is stable in aqueous solution ?
Which of the following does not contain copper
Which sequence of steps describes the best synthesis of $2$ -methyl- $3$ -pentanone ?
→Choose the correct statements about the hydrides of group $15$ elements.
→$A$. The stability of the hydrides decreases in the order $\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3>\mathrm{BiH}_3$
$B$. The reducing ability of the hydrides increases in the order $\mathrm{NH}_3<\mathrm{PH}_3<\mathrm{AsH}_3<\mathrm{SbH}_3<\mathrm{BiH}_3$
$C$. Among the hydrides, $\mathrm{NH}_3$ is strong reducing agent while $\mathrm{BiH}_3$ is mild reducing agent.
$D$. The basicity of the hydrides increases in the order $\mathrm{NH}_3<\mathrm{PH}_3<\mathrm{AsH}_3<\mathrm{SbH}_3<\mathrm{BiH}_3$Choose the most appropriate from the option given below:
$CH_3 -CH_2 -NH_2$ $\xrightarrow[{KOH}]{{CHCl_3}}$ Product
→Atomic number of $ Cr $ and $ Fe$ are $24$ and $26$ respectively. Which of the following is paramagnetic with the spin of electron
→$C{H_3}CN$ is known as acetonitrile because
→In the above reaction find out total product formed as $D$ is.
→Standard electrode potentials of $Zn$ and $Fe$ are known to be $ (i) $ $ - 0.76\,V$ and $ (ii) $ $ - 0.44\,V$ respectively. How does it explain that galvanization prevents rusting of iron while zinc slowly dissolves away
→Name the products in the acid-base reaction :
→$(a)$ $CH_3CH_2NH_2+ HI$
$(b)$ $(CH_3)_3N + HBr$