The correct order of a dipole moment is : - Vidyadip

MCQ

The correct order of a dipole moment is :

✓
$ \mathrm{CH}_4 < \mathrm{NF}_3 < \mathrm{NH}_3 < \mathrm{H}_2 \mathrm{O} $
B
$ \mathrm{NF} < \mathrm{CH}_4 < \mathrm{NH}_3 < \mathrm{H}_2 \mathrm{O} $
C
$ \mathrm{NH}_3 < \mathrm{NF}_3 < \mathrm{CH}_4 < \mathrm{H}_2 \mathrm{O} $
D
$ \mathrm{H}_2 \mathrm{O} < \mathrm{NH}_3 < \mathrm{NF}_3 < \mathrm{CH}_4$

✓

Answer

Correct option: A.

$ \mathrm{CH}_4 < \mathrm{NF}_3 < \mathrm{NH}_3 < \mathrm{H}_2 \mathrm{O} $

The correct order of dipole moment is $ \mathrm{CH}_4 < \mathrm{NF}_3 < \mathrm{NH}_3 < \mathrm{H}_2 \mathrm{O} $.
Methane is zero dipole moment as it is tetrahedral molecule in which $\ce{C−H}$ bond dipoles cancel each other.
In $\ce{NF_3},$ the bond dipole of the lone pair and the resultant dipole of three $\ce{N−F}$ bonds are in opposite direction wheres in ammonia, they are in same direction.
Hence, the dipole moment of $\ce{NF_3}$ is smaller than that of methane.
The dipole moment of water is greater than the dipole moment of ammonia as oxygen is more electronegative than nitrogen.

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