MCQ
The correct order of bond angle is
- A$NCl_3 > NBr_3$
- B$H_2Te > H_2S$
- C$N_3^ - < I_3^ - $
- ✓$NO_3^ - < NO_2^ - $
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$C{H_3} - CH = C{H_2} + HBr\xrightarrow{{{{({C_6}{H_5}CO)}_2}{O_2}}}$