MCQ
The correct order of bond angle
- A$PF_3 < PCl_3 < PBr_3 > PI_3$
- ✓$PF_3 < PCl_3 < PBr_3 < PI_3$
- C$PF_3 > PCl_3 > PBr_3 > PI_3$
- D$PF_3 > PCl_3 < PBr_3 > PI_3$
✓
Answer
Correct option: B.
$PF_3 < PCl_3 < PBr_3 < PI_3$
b
$\mathrm{PI}_{3}>\mathrm{PBr}_{3}>\mathrm{PCl}_{3}>\mathrm{PF}_{3}$
$\mathrm{PI}_{3}>\mathrm{PBr}_{3}>\mathrm{PCl}_{3}>\mathrm{PF}_{3}$
If $\mathrm{C.A}$. $=$ same Hybridisation same
$L.P.$ $=$ same Bond angle $\propto$ size of side atom
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