MCQ
The correct order of electronegativity for given elements is:
- A$C > P > At > Br$
- B$Br > P > At > C$
- C$P > Br > C > At$
- ✓$Br > C > At > P$
| Atom | $E.N$ |
| $Br$ | $3.0$ |
| $C$ | $2.5$ |
| $At$ | $2.2$ |
| $P$ | $2.1$ |
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$N _2 O _3, N _2 O _5, P _4 O _6, P _4 { O }_7, H _4 P _2 O _5, H _5 P _3 O _{10}, H _2 S _2 O _3, H _2 S _2 O _5$


$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.