- ✓$Mn > Cr > Fe > Co$
- B$Cr < Fe > Mn > Co$
- C$Fe > Mn > Cr > Co$
- D$Cr > Mn > Fe > Co$
$E_{M n^{2}+/ M n}^{\circ}=-1.18 V$
$E_{C r^{2}+/ C r}^{\circ}=-0.9 V$
$E_{F e^{2+} / F e}^{\circ}=-0.44 V$ and
$E_{C o^{2}+/ C o}^{\circ}=-0.28 V$
The correct order of $E_{M^{2+} / M}^{\circ}$ values without
considering negative sign would be
$M n^{2+}>C r^{2+}>F e^{2+}>C o^{2+}$
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$E_{F{e^{ + 2}}/Fe}^o =- 0.44\,V$ and $E_{Au/A{u^{ + 3}}}^o = - 1.50\,V$


$Cl_2(aq) + H_2S(aq) \to S(s) + 2H^+(aq) + 2Cl^-(aq)$
The rate equation for this reaction is rate $= k[Cl_2][H_2S]$ Which of these mechanisms is/are consistent with this rate equation ?
$A.\,C{l_2} + {H_2}S \to {H^ + } + C{l^ - } + C{l^ + } + H{S^- }$ (slow)
$C{l^ + } + H{S^ - } \to {H^ + } + C{l^ - } + {S}$ (fast)
$B.\, H_2S \Leftrightarrow H^+ + HS^-$ (fast equilibrium)
$Cl_2 + HS^-\to 2Cl^-+ H^+ + S$ (slow)
| LIST-$I$ | LIST-$I$ |
| $A$.Glucose/NaHCO3/$\Delta$ | $I$.Gluconic acid |
| $B$.Glucose/HNO3 | $II$. No reaction |
| $C$.Glucose/HI/ $\Delta$ | $III$. n-hexane |
| $D$. Glucose/Bromine [water] | $IV$. Saccharic acid |
Choose the correct answer from the options given below:
$(P)\, Fe(CO)_5\,\,\, (Q)\,CO\,\,\, (R)\, H_3B \leftarrow CO\,\,\,(S)\, [Mn(CO)_5]^-$
(consider complete conversion)