- A$Be > Ca > K$
- B$Ca > K > Be$
- ✓$K > Ca > Be$
- D$K > Be > Ca$
$K > Ca > Be$
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Statement $I$: Tropolone is an aromatic compound and has $8 \pi$ electrons.
Statement $II$: $\pi$ electrons of $ > C = O$ group in tropolone is involved in aromaticity.
In the light of the above statements, choose the correct answer from the options given below:
Given $\Delta H$
$(i)\, Fe_2O_{3(s)}+3C_{(graphite)} \to 2Fe_{(s)} + 3CO_{(g)}$ $492\, kJ/mol$
$(ii)\, FeO_{(s)}+C_{(graphite)} \to Fe_{(s)} + CO_{(g)}$ $156\, kJ/mol$
$(iii)\, C_{(graphite)} + O_{2(g)} \to CO_{2(g)}$ $-393 \,kJ/mol$
$(iv)\, CO_{(g)} + \frac{1}{2}\, O_{2(g)} \to CO_{2(g)}$ $-283\, kJ/mol$
$(I){\mkern 1mu} C{H_3}CH_2^ - {\mkern 1mu} + {\mkern 1mu} \mathop {C{H_3}N{H_2}}\limits_{p{K_a} = 35} \rightleftharpoons \mathop {C{H_3}C{H_3}}\limits_{p{K_a} = 50} + C{H_3}N{H^ - }$
$(II){\mkern 1mu} {F^ - }{\mkern 1mu} + {\mkern 1mu} \mathop {{H_2}O}\limits_{p{K_a} = 15.7} \rightleftharpoons \mathop {HF}\limits_{p{K_a} = 3.2} + H{O^ - }$