MCQ
The correct reactivity order for $E_2$ reaction with alcoholic $KOH$ will be


- ✓$i > ii > iii$
- B$ii > iii > i$
- C$i > iii > ii$
- D$iii > i > ii$

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Reason $R : I^{-1}$ is a good nucleophile as well as a good leaving group.
In the light of the above statements, choose the correct answer from the options given below.
$(a)$ $K_2PtCl_6$ $(b)$ $PtCl_4 . 2NH_3$
$(c)$ $PtCl_4 . 3NH_3$ $(d)$ $PtCl_4 . 5NH_3$
Their electrical conductances in aqueous solutions are