The correct relationship between free energy change in a reaction… - Vidyadip

MCQ

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant ${K_c}$ is

A
$\Delta G = RT\ln {K_c}$
B
$ - \Delta G = RT\ln {K_c}$
C
$\Delta {G^o} = RT\ln {K_c}$
✓
$ - \Delta {G^o} = RT\ln {K_c}$

✓

Answer

Correct option: D.

$ - \Delta {G^o} = RT\ln {K_c}$

d
$\because \quad \Delta G =\Delta G ^{\circ}+ RTlnQ$, where $Q$ is reaction quotient at equilibrium, $\Delta G =0$ and $Q = K _{ c }$

$\therefore \quad-\Delta G = RTlnK _{ c }$

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