MCQ
The correct structure of tribromooctaoxide is
- A
- B
- ✓
- D
✓
Answer
Correct option: C.
c
$Xe +2 O _2 F _2 \rightarrow XeF _4+2 O _2$
$Xe +2 O _2 F _2 \rightarrow XeF _4+2 O _2$
$3 XeF _4+6 H _2 O \rightarrow 2 Xe + XeO _3+\frac{3}{2} O _2+12 HF$
$\therefore$ One mole of $XeF _4$ gives 4 moles of $HF$ on hydrolysis.
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