MCQ
The covalency of nitrogen in $HN{O_3}$ is
- A$0$
- B$3$
- C$4$
- ✓$5$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
To obtain high yields of $CH_3Cl$, the ratio of $CH_4$ to $Cl_2$ must be
(Molar mass of $Fe =56\, g\, mol ^{-1}$ )