MCQ
The covalency of nitrogen in $HN{O_3}$ is
  • A
    $0$
  • B
    $3$
  • C
    $4$
  • $5$

Answer

Correct option: D.
$5$
(d) $( + 1) + x + 3( - 2) = 0 \Rightarrow 1 + x - 6 = 0$$ \Rightarrow x = 6 - 1 = 5$.

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