MCQ
The covalency of nitrogen in $HN{O_3}$ is
- A$0$
- B$3$
- C$4$
- ✓$5$
✓
Answer
Correct option: D.
$5$
(d) $( + 1) + x + 3( - 2) = 0 \Rightarrow 1 + x - 6 = 0$$ \Rightarrow x = 6 - 1 = 5$.
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