The current from the cell for the given circuit is ................ $\mathrm{A}$
Medium
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$\mathrm{R}_{\mathrm{eff}}=[(10+6)\|(5+3)\| 16\, \Omega] \,\mathrm{s} \,1\, \Omega$
$\mathrm{R}_{\mathrm{eff}}=5 \,\Omega$
Hence $\mathrm{I}=\frac{\mathrm{E}}{\mathrm{R}_{\mathrm{eff}}}=\frac{60}{5}=12 \mathrm{\,A}$
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