MCQ
The de-Broglie wavelength λ associated with an electron having kinetic energy E is given by the expression
- ✓$\frac{\mathrm{h}}{\sqrt{2} \mathrm{mE}}$
- B$\frac{2 \mathrm{~h}}{\mathrm{mE}}$
- C2 mhE
- D$\frac{2 \sqrt{2 \mathrm{mE}}}{\mathrm{h}}$
✓
Answer
Correct option: A.
$\frac{\mathrm{h}}{\sqrt{2} \mathrm{mE}}$
(a) $\frac{\mathrm{h}}{\sqrt{2} \mathrm{mE}}$
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