The de-Broglie wavelength associated with an electron having kine… - Vidyadip

MCQ

The de-Broglie wavelength $\lambda$ associated with an electron having kinetic energy $E$ is given by the expression

✓
$\frac{h}{\sqrt{2 m E}}$
B
$\frac{2 h}{m E}$
C
$2\ m h E$
D
$\frac{2 \sqrt{2 m E}}{h}$

✓

Answer

Correct option: A.

$\frac{h}{\sqrt{2 m E}}$

$\frac{1}{2} m v^2=E \Rightarrow m v=\sqrt{2 m E} ; $
$\therefore \lambda=\frac{h}{m v}=\frac{h}{\sqrt{2 m E}}$

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