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Product $(B)$ of above reaction
$C{H_3} - CH = C{H_2}\xrightarrow[{CC{l_4}}]{{B{r_2}}}A\xrightarrow[{(3\,\,moles)}]{{\mathop N\limits^ \oplus a\mathop N\limits^\Theta {H_2}}}B\xrightarrow{{C{H_3} - Br}}C\xrightarrow[{{H_2}}]{{Pd + BaS{O_4}}}D$
Statement $I$ : The higher oxidation states are more stable down the group among transition elements unlike p-block elements.
Statement $II$ : Copper can not liberate hydrogen from weak acids.
In the light of the above statements, choose the correct answer from the options given below :
$S{O_2} + N{O_2} \rightleftharpoons S{O_3} + NO$
If we take one mole of each of four gases in one $L$ container. What would be equilibrium concentration of $NO$ and $NO_2$ respectively