MCQ
The decreasing order of boiling points is
- ✓$n-$ Pentane > iso-Pentane > neo-Pentane
- Biso-Pentane > $ n-$ Pentane > neo-Pentane
- Cneo-Pentane > iso-Pentane >$ n-$ Pentane
- D$n-$ Pentane > neo-Pentane > iso-Pentane
So, higher the branches, lower is the boiling point.
So, the order of boiling point of isomeric pentanes is $n -$ pentane $\,>\,$ iso $-$ pentane $\,>\,$ neo $-$ pentane.
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Above reaction is an example of
$(A)$ In $B _{2} H _{6}$, all $B - H$ bonds are equivalent.
$(B)$ In $B _{2} H _{6}$ there are four $3-$centre$-2-$electron bonds.
$(C)$ $B _{2} H _{6}$ is a Lewis acid.
$(D)$ $B _{2} H _{6}$ can be synthesized form both $BF _{3}$ and $NaBH _{4}$.
$(E)$ $B _{2} H _{6}$ is a planar molecule.
Choose the most appropriate answer from the options given below..... .