MCQ
The deficiency of vitamin $-C$ causes
  • Scurvy
  • B
    Rickets
  • C
    Pyrrohea
  • D
    Pernicious Anaemia

Answer

Correct option: A.
Scurvy
a
Vitamin $C$ called ascorbic acid deficiency causes a disease called scurvy that is symptomized by the broken corners of lips. The fruits that are rich in vitamin $c$ are the citrus fruits. Rickets is caused by the deficiency of vitamin $D$. Pernicious anemia is caused by the deficiency in vitamin $B_{12}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The highest boiling point is expected for
Consider, $PF _{5}, BrF _{5}, PCl _{3}, SF _{6},\left[ ICl _{4}\right]^{-}, ClF _{3}$ and $IF _{5}$

Amongst the above molecule(s)/ion(s), the number of molecule(s)/1on(s) having $sp ^{3} d ^{2}$ hybridisation is $........$

Select equations having endothermic step

$(A)\,S_{\left( g \right)}^ - \,\, \to \,\,S_{\left( g \right)}^{2 - }\,$

$(B)\,Na_{\left( g \right)}^ + \, + \,Cl_{\left( g \right)}^ - \,\, \to \,\,NaCl\,(s)$

$(C)\,{N_{\left( g \right)}}\, \to \,\,N_{\left( g \right)}^ - $

$(D)\,Al_{\left( g \right)}^{2 + }\, \to \,\,Al_{\left( g \right)}^{3 + }$

Consider an imaginary ion ${ }_{22}^{48} X ^{3-}$. The nucleus contains 'a'$\%$ more neutrons than the number of electrons in the ion. The value of '$a$' is $.....$ [nearest integer]
The major product formed in the reaction is
In double strand helix structure of $DNA,$  thymine forms hydrogen bonds with
Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.

Assertion $A$ : Boric acid is a weak acid

Reason $R$ : Boric acid is not able to release $H ^{+}$ion on its own. It receives $OH ^{-}$ion from water and releases $H ^{+}$ion.

In the light of the above statements, choose the most appropriate answer from the options given below.

In the following structure, the double bonds are marked $I$, $II$, $III$ and $IV$.
$V-A$ group precipitate was dissolved in $HN{O_3}$ and treated with excess of $N{H_4}OH$. It gives a white ppt. because of
Le-Chatelier’s principle is applicable only to a