MCQ
The degree of differential equation $[1+(\frac{\text{dy}}{\text{dx}})^2]^{\frac{1}{2}}=\frac{\text{d}^2\text{y}}{\text{dx}^2}$ is:
- A$4$
- B$\frac{3}{2}$
- ✓$2$
- DNot defined
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