MCQ
The determinant $\left| {\,\begin{array}{*{20}{c}}{4 + {x^2}}&{ - 6}&{ - 2}\\{ - 6}&{9 + {x^2}}&3\\{ - 2}&3&{1 + {x^2}}\end{array}\,} \right|$ is not divisible by
- A$x$
- B${x^3}$
- C$14 + {x^2}$
- ✓${x^5}$
Hence, the determinant is divisible by $x$,${x^3}$ and $(14 + {x^2})$,
but not divisible by ${x^5}$.
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($1$) $P(X>Y)$ is
($A$) $\frac{1}{4}$ ($B$) $\frac{5}{12}$ ($C$) $\frac{1}{2}$ ($D$) $\frac{7}{12}$
($2$) $P(X=Y)$ is
($A$). $\frac{11}{36}$ ($B$) $\frac{1}{3}$ ($C$) $\frac{13}{36}$ ($D$) $\frac{1}{2}$
Given the answer quetion ($1$) and ($2$)