Linear Equations in One Variable — MATHS STD 8 — Question
Gujarat BoardEnglish MediumSTD 8MATHSLinear Equations in One Variable5 Marks
Question
The difference between the squares of two consecutive numbers is $31$. Find the numbers.
✓
Answer
Let the requierd number $= x$
Then Four-fifth of the number $= x + 1$
$\therefore$ According to the condition:
$(x + 1)^2- (x)^2= 31$
$\Rightarrow x^2+ 2x + 1 - x^2= 31$
$\Rightarrow 2x = 31 - 1 = 3030$
$\Rightarrow\text{x}=\frac{30}{2}=15$
$\therefore$ First number $= 15$
And second number $= 15 + 1 = 16$
Hence numbers are $15, 16$
Check: $(16)^2- (15)^2= 256 - 225 = 31$
Which is given
$\therefore$ Our answer is correct.
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