MCQ
The differential equation $\cot y\,\,dx = x\,\,dy$ has a solution of the form
  • A
    $y = \cos x$
  • $x = c\sec y$
  • C
    $x = \sin y$
  • D
    $y = \sin x$

Answer

Correct option: B.
$x = c\sec y$
b
(b) $\cot y.dx = x.dy$ ==> $\frac{{dx}}{x} = \frac{{dy}}{{\cot y}}$ ==> $\frac{{dx}}{x} = \tan y.dy$

Integrating both sides,

$\log x = \log \sec y + \log c$ ==> $x = c\sec y$.

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