- ANeither time nor concentration
- BOnly time
- ✓Time and concentration
- DTime and square of concentration
Rate Law for this Reaction is given by : Rate $= k [ A ]^2$
$\because$ Unit of Rate of Reaction is $mol \,litre { }^{-1} \,\sec ^{-1}$ and Unit of Concentration is $mol\, litre ^{-1}$
$\therefore$ Unit of Rate constant is $mol ^{-1}\, litre\,sec ^{-1}$
$\Rightarrow$ Unit of Rate constant is $\left( mol \text { litre }^{-1}\right)^{-1}\, sec ^{-1}$
Unit of Rate constant is $(concentration) { }^{-1} \,\sec ^{-1}$
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$V. P.$ of pure $B$ $p^o_B = 150\,mmHg$
A solution containing $2\,moles$ $A$ and $3\,moles$ $B$ will have total vapour pressure, approximately, on condensation ......... $mm$.
Reason : In mercury cell, the electrolyte is a paste of $KOH$ and $ZnO$.
$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad$(Yellow coloured compound)
Consider the above reaction, the Product $"P"$ is:
$Zn(s) + Cu^{2+}(M) \to Zn^{2+}(M') + Cu(s);$ $E^o _{cell} = 1.10\,V$
$X$-axis :$log_{10}$ $\frac{{[Z{n^{2 + }}]}}{{[C{u^{2 + }}]}}$, $Y$ -axis : $E_{cell}$