MCQ
The dimensional formula for the physical quantityis $\frac{{{E^2}{\mu _0}{\varepsilon _0}}}{{{B^2}}}$ ($E =$ electric field and $B =$ magnetic field)
- A$L^0M^0T^0$
- B$L^1M^0T^{-1}$
- C$L^{-1}M^0T^1$
- D$L^{1/2}M^0T^{-1/2}$
✓
Answer
We know,
$\mu_0 \varepsilon_0=\frac{1}{ c ^2}$
$\frac{E}{B}=c$
$\frac{ E ^2 \mu_0 \varepsilon_0}{ B ^2}=1$
Dimension of $1=\left[ M ^0 L ^0 T ^0\right]$
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