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Motion in One Dimension — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsMotion in One Dimension1 Mark
MCQ
The displacement is given by $x=2 t^2+t+5$, the acceleration at $t=2 s$ is
  • ✓
    $4 m / s ^2$
  • B
    $8 m / s ^2$
  • C
    $10 m / s ^2$
  • D
    $15 m / s ^2$
✓

Answer

Correct option: A.
$4 m / s ^2$
(a) Displacement $x=2 t^2+t+5$Velocity $=\frac{d x}{d t}=4 t+1$Acceleration (=\frac{d^2 x}{d t^2}=4$ i.e. independent of time\text { Hence acceleration }=4 \mathrm{~m} / \mathrm{s}^2

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