The displacement of a particle executing simple harmonic motion is given by
$\mathrm{y}=\mathrm{A}_{0}+\mathrm{A} \sin \omega \mathrm{t}+\mathrm{B} \cos \omega \mathrm{t}$
Then the amplitude of its oscillation is given by
NEET 2019, Medium
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$y=A_{0}+A \sin \omega t+B \cos \omega t$
$y=A_{0}+\sqrt{A^{2}+B^{2}} \sin (\omega t+\phi)$
$\mathrm{A}_{0}$ is mean position, and $\sqrt{\mathrm{A}^{2}+\mathrm{B}^{2}}$ is amplitude
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