The displacement time graph of a particle executing $S.H.M.$ is as shown in the figureThe corresponding force-time graph of the particle is
A
B
C
D
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D
d (d)Acceleration $ = - {\omega ^2}y.$ So $F = - m{\omega ^2}y$
$y$ is sinusoidal function.
So $F$ will be also sinusoidal function with phase difference $\pi$
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