MCQ
The distance between $3^{rd}$ and $2^{nd}$ Bohr's orbits in the hydrogen atom is
- ✓$2.646\, \times \, 10^{-8}\, cm$
- B$2.116\, \times \, 10^{-8}\, cm$
- C$1.058\, \times\, 10^{-8}\, cm$
- D$0.529\, \times\, 10^{-8}\, cm$
✓
Answer
Correct option: A.
$2.646\, \times \, 10^{-8}\, cm$
a
${r_3} - {r_2} = 0.529\left( {\frac{{{3^3}}}{1} - \frac{{{2^2}}}{1}} \right)$
${r_3} - {r_2} = 0.529\left( {\frac{{{3^3}}}{1} - \frac{{{2^2}}}{1}} \right)$
$ = 0.529 \times 5$
$ = 2.645\,\mathop A\limits^o $
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