MCQ
The distance between (6, 5) and (-3, 4) is:
- A$\sqrt{82}$
- B$\sqrt{83}$
- C$\sqrt{84}$
- DNone
The distance between (6, 5) and (-3, 4) is:
Solution:
The given points are (6, 5) and (-3, 4)
The distance is given as $=\sqrt {(\text{x}_2-\text{x}_1)^2+(\text{y}_2-\text{y}_1)^2}$
$=\sqrt {(6+3)^2+(4-5)^2}$
$=\sqrt {9^2+1^2}$
$=\sqrt {81+1}=\sqrt {82}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
What is the radius of the circle passing through the point (2, 4) and having centre at the intersection of the lines 4x - y = 4 and 2x + 3y + 7?
The probability that at least one of the events A and B occurs is 0.6. If A and B occur simultaneously with probability 0.2, then $\text{P}(\bar{\text{A}})+\text{P}(\bar{\text{B}})$ is: