MCQ
The domain of ${\sin ^{ - 1}}({\log _3}x)$ is
- A$[-1, 1]$
- B$[0, 1]$
- C$[0, \infty $]
- ✓$ \left[ {\frac{1}{3},\,3} \right]$
==> $\frac{1}{3} \le x \le 3$
$\therefore$ Domain of function $ = \left[ {\frac{1}{3},\,3} \right]$.
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$(A)$ $ \equiv \frac{{x + 1}}{1} = \frac{{y - 2}}{{ - 2}} = \frac{{z - 0}}{1}$
$(B)$ $ \equiv \frac{x}{1} = \frac{y}{{ - 2}} = \frac{{z - 1}}{1}$
$(C)$ $ \frac{{x + 1/2}}{1} = \frac{{y - 1}}{{ - 2}} = \frac{{z - 1/2}}{1}$