MCQ
The domain of ${\sin ^{ - 1}}({\log _3}x)$ is
- A$[-1, 1]$
- B$[0, 1]$
- C$[0, \infty $]
- ✓$ \left[ {\frac{1}{3},\,3} \right]$
==> $\frac{1}{3} \le x \le 3$
$\therefore$ Domain of function $ = \left[ {\frac{1}{3},\,3} \right]$.
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