MCQ
The domain of the function $\text{f}(\text{x})=\frac{\text{x}}{(1+\text{x}^2)}$ is:
- AR - {1}
- BR - {-1}
- CR
- DNone of these
Solution:
Given, function $\text{f}(\text{x})=\frac{\text{x}}{(1+\text{x}^2)}$
Since f(x) is defined for all real values of x
So, domain(f) = R.
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Let R be set of points inside a rectangle of sides a and b (a, b > 1) with two sides along the positive direction of x-axis and y-axis. Then
$\text{x}\in\text{R}$
$\text{x}\in\text{Q}$
$\text{x}\in\text{R}-\text{Q}$
$\text{x}\in\text{R},\text{ x}\neq0$