MCQ
The domain of the function $f(x) = \log (\sqrt {x - 4} + \sqrt {6 - x} )$ is
- A$[4,\infty )$
- B$( - \infty ,\;6]$
- ✓$[4,\;6]$
- DNone of these
==> $y = {x^x}\, \Rightarrow \,\,\,\log y = x\log x$ and $6 - x \ge 0$==>$x \ge 4$ and $x \le 6$
$\therefore $ Domain of $f(x)$ = $[4,\,\,6]$.
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$f(x) = \left\{ {\begin{array}{*{20}{c}}
{\frac{{{e^{\frac{1}{{x - 1}}}} - 2}}{{{e^{\frac{1}{{x - 1}}}} + 2}}}&{x \ne 1}\\
{1\,\,\,\,\,\,\,\,\,\,\,\,\,}&{x = 1}
\end{array}} \right.$