MCQ
The electronic configuration of halogen is
- A$n{s^2}n{p^6}$
- B$n{s^2}n{p^3}$
- ✓$n{s^2}n{p^5}$
- D$n{s^2}$
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$(I)$ As wavelength decreases, the lines in the series converge
$(II)$ The integer $n_{1}$ is equal to $2$
$(III)$ The lines of longest wavelength corresponds to $\mathrm{n}_{2}=3$
$(IV)$ The ionization energy of hydrogen can be calculated from wave number of these lines
[Given: The threshold frequency of platinum is $1.3$ $\times 10^{15} \,s ^{-1}$ and $h =6.6 \times 10^{-34} \,J \,s$.]