MCQ
The electronic structure of four elements $A, B, C, D$ are
- A$1{s^2}$
- B$1{s^2},\,\,2{s^2}\,2{p^2}$
- ✓$1{s^2},\,\,2{s^2}\,2{p^5}$
- D$1{s^2},\,\,2{s^2}\,2{p^6}$
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$Cr _2 O _7^{2-}+ XH ^{+}+6 Fe ^{2+} \rightarrow YCr ^{3+}+6 Fe ^{3+}+ ZH _2 O$
The sum of $X . Y$ and $Z$ is $.......$.
${{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}+4[H]\xrightarrow{\text{Red P}+\text{HI}}2X+{{H}_{2}}O,$ $X$ is
$\mathrm{PF}_5, \mathrm{BrF}_5, \mathrm{PCl}_5,\left[\mathrm{PtCl}_4\right]^{2-}, \mathrm{BF}_3, \mathrm{Fe}(\mathrm{CO})_5$
The direct reaction of xenon with fluorine leads to a series of compounds with oxidation numbers $+2,+4$ and $+6$ . XeF $4$ reacts violently with water to give $\mathrm{XeO}_3$. The compounds of xenon exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell.
$1.$ Argon is used in arc welding because of its
$(A)$ low reactivity with metal
$(B)$ ability to lower the melting point of metal
$(C)$ flammability
$(D)$ high calorific value
$2.$ The structure of $\mathrm{XeO}_3$ is
$(A)$ linear $(B)$ planar $(C)$ pyramidal $(D)$ $T$-shaped
$3.$ $\mathrm{XeF}_4$ and $\mathrm{XeF}_6$ are expected to be
$(A)$ oxidizing $(B)$ reducing $(C)$ unreactive $(D)$ strongly basic
Give the answer question $1,2$ and $3.$
Here $A$ and $B$ on hydrolysis respectively gives