- A$Ag$
- B$Fe$
- C$Sn$
- ✓$Pb$
$Fe ^{3+}$ ion is more stable due to its half-filled $3 d ^5$ electron configuration. As half filled and completely filled shells are more stable $Fe ^{3+}$ ion is more stable than $Fe ^{2+}$
The $Sn ^{2+}$ ions convert to $Sn ^{4+}$ ions because the tin$(IV)$ oxidation state is more stable than tin$(II)$.
In non-transition elements of p-block, lower oxidation state is more stable due to inert pair effect e.g., $Pb ^{2+}$ is more stable than $Pb ^{4+}$
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The above reaction is carried out in a vessel starting with partial pressure $\mathrm{P}_{\mathrm{SO}_{2}}=250\, \mathrm{~m}$ $bar,$ $\mathrm{P}_{0_{2}}=750 \,\mathrm{~m}$ $bar$ and $\mathrm{P}_{\mathrm{SO}_{3}}=0 \,\mathrm{bar}$. When the reaction is complete, the total pressure in the reaction vessel is $.....\mathrm{m}$ $bar.$ (Round off to the Nearest Integer).