MCQ
The element of second row and third column in the inverse of $\left[\begin{array}{ccc}1 & 2 & 1 \\ 2 & 1 & 0 \\ -1 & 0 & 1\end{array}\right]$ is
  • A
    $-2$
  • $-1$
  • C
    $1$
  • D
    $2$

Answer

Correct option: B.
$-1$
(B) Let $A=\left[\begin{array}{ccc}1 & 2 & 1 \\ 2 & 1 & 0 \\ -1 & 0 & 1\end{array}\right] \Rightarrow|A|=-2 \neq 0$
Now, co-factor of element $a _{32}$ of $A = A _{32}$
$\therefore \quad A _{32}=(-1)^{3+2}\left|\begin{array}{ll}1 & 1 \\ 2 & 0\end{array}\right|=2$
$\therefore \quad$ Element $a _{23}$ of $A ^{-1}=\frac{ A _{32}}{|A|}=\frac{2}{-2}=-1$
Alternate method:
$|A|=-2 \neq 0$
$\operatorname{adj} A=\left[\begin{array}{ccc}1 & -2 & -1 \\ -2 & 2 & 2 \\ 1 & -2 & -3\end{array}\right]$
$\therefore \quad A^{-1}=\left[\begin{array}{ccc}-\frac{1}{2} & 1 & \frac{1}{2} \\ 1 & -1 & -1 \\ -\frac{1}{2} & 1 & \frac{3}{2}\end{array}\right]$
$\therefore \quad$ Element $a _{23}$ of $A ^{-1}=-1$.

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