MCQ
The emissive power per wavelength interval $R_\lambda$ of a blackbody at an absolute temperature $T_1$ is maximum at $\lambda_1=1.1 \mu \mathrm{m}$. At an absolute temperature $T_2$, its $R_\lambda$ is maximum at $\lambda_2=0.55$ $\mu \mathrm{m}$. Then, $\frac{T_1}{T_2}$ is equal to
- ✓$\frac{1}{2}$
- B1
- C2
- D4.
