- AA catalyst is used
- BAn adsorbent is used to remove $S{O_3}$ as soon as it is formed
- CLow pressure
- DSmall amounts of reactants are used
When an adsorbent removes $SO _3$ as soon as it is formed, the equilibrium will shift in the forward direction so that more and more $SO _3$ is formed which will nullify the effect of decrease in the concentration of product.
When small amounts of reactants are removed, the equilibrium will shift in the backward direction so as to nullify the effect of decrease in the reactant concentration.
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$(C= 3 \times 10^8 \,ms^{-1}$ and $N_A =6.02 \times mol^{-1}).$
$(A)$ Uncertainty principle rules out the existence of definite paths for electrons.
$(B)$ The energy of an electron in $2 s$ orbital of an atom is lower than the energy of an electron that is infinitely far away from the nucleus.
$(C)$ According to Bohr's model, the most negative energy value for an electron is given by $n=1$, which corresponds to the most stable orbit.
$(D)$ According to Bohr's model, the magnitude of velocity of electrons increases with increase in values of $n$.
$2NH_3 + 5F_2\,\,\to \,\, N_2F_4 + 6HF$