The equilibrium constant for the given reaction H_2 + I_2 2HI is … - Vidyadip

MCQ

The equilibrium constant for the given reaction ${H_2} + {I_2}$ $\rightleftharpoons$ $2HI$ is correctly given by expression

A
${K_c} = \frac{{[{H_2}][{I_2}]}}{{[HI]}}$
B
${K_c} = \frac{{[{H_2}][{I_2}]}}{{[2HI]}}$
C
${K_c} = \frac{{[{H_2}][{I_2}]}}{{{{[HI]}^2}}}$
✓
${K_c} = \frac{{{{[HI]}^2}}}{{[{H_2}][{I_2}]}}$

✓

Answer

Correct option: D.

${K_c} = \frac{{{{[HI]}^2}}}{{[{H_2}][{I_2}]}}$

d
$H _2+ I _2=2 HI$

$K _{ C }$ for a reaction $aA + bB \rightleftharpoons cC + dD$

$\Rightarrow \frac{[ C ]^{ c }[ D ]^{ d }}{[ A ]^{ a }[ B ]^{ b }}$

So here $K _{ C }=\frac{[ HI ]^2}{\left[ H _2\right]\left[ I _2\right]}$

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