The equivalent resistance between the points $P$ and $Q$ in the network given here is equal to ................ $\Omega$ (given $r = \frac{3}{2}\Omega $)
A$\frac{1}{2}$
B$1$
C$\frac{3}{2}$
D$2$
Medium
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B$1$
b (b) The given circuit can be simplifies as follows
$R' = \frac{{2r}}{3} = \frac{2}{3} \times \frac{3}{2} = 1\Omega $.
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