MCQ
The equivalent weight of ${K_2}C{r_2}{O_7}$ in acidic medium
- A$294$
- B$298$
- ✓$49$
- D$50$
✓
Answer
Correct option: C.
$49$
c
(c) ${K_2}C{r_2}{O_7} + 3{H_2}S{O_4}\, \to {K_2}S{O_4} + C{r_2}{(S{O_4})_3} + 3\,(O) + 3{H_2}$
(c) ${K_2}C{r_2}{O_7} + 3{H_2}S{O_4}\, \to {K_2}S{O_4} + C{r_2}{(S{O_4})_3} + 3\,(O) + 3{H_2}$
No. of electrons lossed $= 12 -6 = 6$
Equivalent weight $=\frac{M}{6} = \frac{{294}}{6} = 49$ .
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