MCQ
The equivalent weight of potassium permanganate for acid solution is
- A$158$
- ✓$31.6$
- C$52.16$
- D$79$
Equivalent weight $= \frac{{158}}{5}$ $= 31.6$
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$3.0$ $moles$ of $\mathrm{PCl}_{5}$ is introduced in a $1\, \mathrm{~L}$ closed reaction vessel at $380\, \mathrm{~K}$. The number of moles of $\mathrm{PCl}_{5}$ at equilibrium is $.....\,\times 10^{-3}$. (Round off to the Nearest Integer)