MCQ
The factorisation $1+16 x+64 x^{2}$ is
  • A
    $(1-8 x)^{2}$
  • $(1+8 x)^{2}$
  • C
    $(8-x)^{2}$
  • D
    $(8+x)^{2}$

Answer

Correct option: B.
$(1+8 x)^{2}$
b
$1+16 x+64 x^{2}$
$=(1) 2+2(1)(8 x)+(8 x)^{2}=(1+8 x)^{2}$

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